How Do I Properly Expose Dark Scenes Containing Bright Light Sources?

How do I properly expose dark scenes containing bright light sources?

How Do I Properly Expose Dark Scenes Containing Bright Light Sources? 1

You can not . You cannot adjust the contrast difference between the light source and the scene. Even if you dim the light source, you will be dimming the scene proportionally, if the light source is the major illuminant.If the scene is lit by a combination of light sources (e. g. ambient window light and a lamp) then you can change the ratio of these sources by modifying one of them (usually the lamp), by either turning it up (not likely) or adding a ND filter in front of it to reduce its contribution. However, looking at your scene it does not look like you have control of any of the light sources (windows or billboard flood).You are therefore left with manipulating the image in post. You can take two frames, one exposing for correct exposure of the background (e.g. ceiling) and a second image at -2 EV or so, to capture highlights in the light sources and reduce speculars. You would then combine these two by masking.

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There is no chandelier or any light source in my room but there's an on off switch?

I am sure that switch controls the outlets and you would plug a lamp into it or re-wire a standard light fixture with a cord and plug. Mount the fixture on the wall or ceiling then run the cord over and down to the outlet

How Do I Properly Expose Dark Scenes Containing Bright Light Sources? 2

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Why is it recommended for schools or other institutions for their rooms to preferably have a light source from the left side?

Educationists, particularly from the UK, provide some advice on how to write and read more efficiently. One among them refers to the lighting conditions. Since a large majority of the learner's are right handed, for efficient lighting during study period, both reading and writing, the book or the paper on which to write should be shadow free. That is why the light source should be on the left side of the person studying. This is applicable to both table lights and room lights, particularly for the former.Why is it recommended for schools or other institutions for their rooms to preferably have a light source from the left side?.

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A box, completely mirrored on the inside w/ a light source. When the light is turned off does the interior?

Um.....'cause there is no light

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Is there a difference between a large, far light source, and a small, close one?

They say a picture paints a thousand words, so I will augment the existing answers with a basic MS Paint representation.The falloff is depicted by the yellow curves below the light paths. It's very rough, but given an 1/r falloff, you can see how the falloff is much more gradual from the light source furthest from the subject.

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What would you see if you inserted a light source?

First, let's face reality about transmission. The transmission of a mirror (transmittance = percent of incident light which gets through) is always the same in both directions. Reflection, however, (reflectance = percent of light which is reflected) can be different from both directions. This is sometimes used to make "one way glass" where the transmitted light is harder to distinguish due to the brighter reflection from one side. The visual effect is even stronger when the more reflective side is also more highly illuminated. Now, to answer your original question. Yes, you would see light because one way mirror glass does transmit some light. The amount of light inside would build up, getting brighter and brighter, until the rate at which light is lost is equal to the rate at which light is being added. Light will be lost by both transmission and by absorption (for example, by the light bulb). Indeed people have done experiments like this! The vast majority of lasers take advantage of this effect. The beam bounces back and forth between two mirrors (yes it could be a full sphere, but because the beam is coherent, only the smaller mirrors are necessary). The light that comes out is actually leakage through one of the end mirrors. Now what about your "super mirror", where no light can escape? In that case, you would not see light, since none would escape. Keep in mind, of course, that it is no longer "one way mirror glass". But what would happen inside the sphere? As with the laser, the light inside would build up until the rate light is lost equals the rate light is added. With no transmission, the only loss left is absorption, either by the mirror or by the light bulb. Things would heat up until something stops working. But what if you had a super mirror which reflected absolutely all of the light and a super light bulb and vacuum which absorbed absolutely no light? Then the light inside would continue to grow and grow unless something fails, either the mirror, the bulb or the vacuum itself. In that case, all bets are off!

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