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# Red White and Blue Bulbs.?

red white and blue bulbs.?

It all depends on the size of your enclosure. wattage depends on the size of your enclosure. UVA and UVB come in white light, good for 14 hours a day. If you want heat through the night you can use red or blue. But if your not going to view them ALL night, then you might want to look at getting a ceramic heat emmiter connected to your thermostat to control your night temps.

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Michelson interferogram white light pattern symmetry

If we assume the wave-fronts that initially enter the system to produce this image are symmetric, than the result is intuitively symmetric as all the components used to produce it are too. And anyone who looks at the images you have shown, will clearly see a symmetry about the Y-axis. Assuming they do not look for minuscule errors due to wave-front discontinuity.Let's make sure we have all the right ideas by verifying the definition of "symmetry". "Symmetry across a Y-axis" is a reflectional symmetry. Meaning that both sides, if split down the center and one side flipped, are equal to each-other.I suppose the other question is why this symmetry is visible for such a system? It was made using a "Michelson Interferometer", if we look at such a device it is clearly also reflectively symmetric (Neat). Now, keep in mind that all wave fronts curve. Given the reflective path, the wave-fronts on the edge would start to fall further behind the center wave-front, giving it a different position. The shorter path will have edge wave-fronts in different positions than the longer path. This will create the interference we see. Both paths are almost equal, we are talking about a difference in distance on the order of fractions of wavelengths.Hope that helps.EDIT:Due to the nature of any light source, the vibrating particles making the light can be out of sink with each-other. This is not true for a laser, once the laser is started the selected waveform for that laser will reinforce the motion of the particles, making them move in synchronization with each-other. If the particles producing the light are moving together the discontinuities will diminish.

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Why do we see the sun as yellow rather than white?

Actually, it's not seen as yellow because it is yellow. It's seen as yellow because we have an atmosphere. Remember that every star outputs all wavelengths of light in sort of a "bell curve" with a peak corresponding to it's temperature. The sun actually peaks very close to green, but this means that it also puts out roughly equal amounts of red and blue. When you sum those colors, you get white light (which is why there are no green stars, BTW). When the light gets to our atmosphere, it is scattered, but the blue (and violet) light is scattered more than the reds and oranges. When you take a white light and subtract some of the blue, you get yellow. The yellow that we see from the sun, plus the blue in the sky, make white.

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chlorine formed in hydrochloric acid

The color could be due to other impurities, such as iron. That might also be harsh on delicate RO membranes, perhaps by precipitating a floc on the membrane.If it is iron, neutralizing with clear alkali (NaOH or KOH) to pH 6-7 would precipitate a floc. Take a flashlight with a very narrow beam of white light and shine it thru the neutralized solution. If the beam lights up like a beam of light in a smoke-filled room, you have a precipitate. There are inexpensive LED flashlights that are perfect for this. Red lasers might not show the scattered beam as well.

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White Light

White Light is a full-length album released by the British electronic music duo Groove Armada in 2010. It consists alternative versions of songs from their previous album, Black Light, along with one new song entitled "1980"

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[Ramadan] I have seen a mysterious white light?

It has nothing to do with religion I mean when I was 14 when I squeeze the corner of my eye near the nose rainbow colors appear with surging pain

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Colored fringes in Young's Double Slit Experiment (YDSE) using white light

White light (e.g. sunlight) consists of many different wavelengths of light (not only 7 btw). Each wavelength has a different diffractive index, with longer wavelengths (red) diffracting more than short wavelengths (blue). This means that for each wavelength you will get an interference pattern with a different distance between the maxima (see image)In the centre these maxima line up and you get a white spot. Away from the centre the peaks no longer line up and we get a "rainbow effect".If you have a functional form for the intensity \$I_lambda(x)\$ for a given wavelength, and an initial distribution for the wavelengths in your white light \$p(lambda)\$ (called the relative intensity or power density), then your new distribution of frequencies will be proportional to \$I_lambda(x)p(lambda)\$.To answer the final part of your question, the minima will no longer be completely dark, because a minima for one wavelength will not be a minima for another. Just looking at the intensity of light (and not the colour) would give something like the image below, which does not have perfect minima

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